4c^3+4c^2-80c=0

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Solution for 4c^3+4c^2-80c=0 equation:


Simplifying
4c3 + 4c2 + -80c = 0

Reorder the terms:
-80c + 4c2 + 4c3 = 0

Solving
-80c + 4c2 + 4c3 = 0

Solving for variable 'c'.

Factor out the Greatest Common Factor (GCF), '4c'.
4c(-20 + c + c2) = 0

Factor a trinomial.
4c((-5 + -1c)(4 + -1c)) = 0

Ignore the factor 4.

Subproblem 1

Set the factor 'c' equal to zero and attempt to solve: Simplifying c = 0 Solving c = 0 Move all terms containing c to the left, all other terms to the right. Simplifying c = 0

Subproblem 2

Set the factor '(-5 + -1c)' equal to zero and attempt to solve: Simplifying -5 + -1c = 0 Solving -5 + -1c = 0 Move all terms containing c to the left, all other terms to the right. Add '5' to each side of the equation. -5 + 5 + -1c = 0 + 5 Combine like terms: -5 + 5 = 0 0 + -1c = 0 + 5 -1c = 0 + 5 Combine like terms: 0 + 5 = 5 -1c = 5 Divide each side by '-1'. c = -5 Simplifying c = -5

Subproblem 3

Set the factor '(4 + -1c)' equal to zero and attempt to solve: Simplifying 4 + -1c = 0 Solving 4 + -1c = 0 Move all terms containing c to the left, all other terms to the right. Add '-4' to each side of the equation. 4 + -4 + -1c = 0 + -4 Combine like terms: 4 + -4 = 0 0 + -1c = 0 + -4 -1c = 0 + -4 Combine like terms: 0 + -4 = -4 -1c = -4 Divide each side by '-1'. c = 4 Simplifying c = 4

Solution

c = {0, -5, 4}

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